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Question Number 56818 by Gulay last updated on 24/Mar/19

Commented by Gulay last updated on 24/Mar/19

$$\mathrm{sir}\mathrm{plz}\mathrm{help}\mathrm{me}$$

Commented by tanmay.chaudhury50@gmail.com last updated on 24/Mar/19

$$foreqn{ax}^2+bx+c=0$$$$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$$$noweqn{x}^2-2004x+50=0$$$$comparingwith{ax}^2+bx+c=0$$$$a=1b=-2004c=50$$$$x=\frac{2004\pm \sqrt{{\left(2004\right)}^2-4\times 1\times 50}}{2}$$$$=\frac{2004\pm \sqrt{{\left(2004\right)}^2-200}}{2}$$$$=\frac{2004\pm 2003.95}{2}$$$$=\frac{4007.95}{2}and\frac{0.05}{2}$$$$=2003.975and0.025$$$$inthiswaysolveotherstwo...$$$$2)a=1b=2006c=-3$$$$x=\frac{-2006\pm \sqrt{{\left(2006\right)}^2-4\times 1\times (-3)}}{2}$$$$=\frac{-2006\pm \sqrt{{\left(2006\right)}^2+12}}{2}$$$$nowplsusecalculator..$$

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