Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 56824 by Gulay last updated on 24/Mar/19

Commented by Gulay last updated on 24/Mar/19

$$\mathrm{sir}\mathrm{could}\mathrm{you}\mathrm{help}\mathrm{me}$$

Answered by tanmay.chaudhury50@gmail.com last updated on 24/Mar/19

$$4^x\times 4^2+3\times 4^x=76$$$$4^x=a$$$$16a+3a=76$$$$19a=76$$$$a=4so{4}^x=4^1$$$$x=1$$

Answered by kelly33 last updated on 25/Mar/19

$$4^{x+2}+3.4^x=76$$$$4^x.4^2+3.4^x=76$$$$Suposition{4}^x=y$$$$16y+3y=76$$$$19y=76$$$$y=\frac{76}{19}$$$$y=4$$$$$$$$4^x=4^1$$$$x=1$$$$$$$$$$

Commented by Gulay last updated on 25/Mar/19

$$\mathrm{thanks}\mathrm{sir}$$$$$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com