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Question Number 56861 by Hassen_Timol last updated on 25/Mar/19

At 20°C, the solubility of Methoxymethane  in water is 71.0 g.L^(−1) , however, ethanol and  water are miscible.        Given that :  •     Ethanol : H_3 C−C−O  •     Methoxymethane : H_3 C−O−CH_3   •     X(H)=2.2 , X(C)=2.6 , X(O)=3.4     Considering the polarity of these solvents  and molecules, how do you explain the  difference between the soulubility of  ethanol and Methoxymethane in water ?     Thank you

$$\mathrm{At}\:\mathrm{20}°\mathrm{C},\:\mathrm{the}\:\mathrm{solubility}\:\mathrm{of}\:\mathrm{Methoxymethane} \\ $$$$\mathrm{in}\:\mathrm{water}\:\mathrm{is}\:\mathrm{71}.\mathrm{0}\:\mathrm{g}.\mathrm{L}^{−\mathrm{1}} ,\:\mathrm{however},\:\mathrm{ethanol}\:\mathrm{and} \\ $$$$\mathrm{water}\:\mathrm{are}\:\mathrm{miscible}. \\ $$$$\: \\ $$$$\:\:\:\mathrm{Given}\:\mathrm{that}\:: \\ $$$$\bullet\:\:\:\:\:\mathrm{Ethanol}\::\:\mathrm{H}_{\mathrm{3}} \mathrm{C}−\mathrm{C}−\mathrm{O} \\ $$$$\bullet\:\:\:\:\:\mathrm{Methoxymethane}\::\:\mathrm{H}_{\mathrm{3}} \mathrm{C}−\mathrm{O}−\mathrm{CH}_{\mathrm{3}} \\ $$$$\bullet\:\:\:\:\:\mathcal{X}\left(\mathrm{H}\right)=\mathrm{2}.\mathrm{2}\:,\:\mathcal{X}\left(\mathrm{C}\right)=\mathrm{2}.\mathrm{6}\:,\:\mathcal{X}\left(\mathrm{O}\right)=\mathrm{3}.\mathrm{4} \\ $$$$\: \\ $$$$\mathrm{Considering}\:\mathrm{the}\:\mathrm{polarity}\:\mathrm{of}\:\mathrm{these}\:\mathrm{solvents} \\ $$$$\mathrm{and}\:\mathrm{molecules},\:\mathrm{how}\:\mathrm{do}\:\mathrm{you}\:\mathrm{explain}\:\mathrm{the} \\ $$$$\mathrm{difference}\:\mathrm{between}\:\mathrm{the}\:\mathrm{soulubility}\:\mathrm{of} \\ $$$$\mathrm{ethanol}\:\mathrm{and}\:\mathrm{Methoxymethane}\:\mathrm{in}\:\mathrm{water}\:? \\ $$$$\: \\ $$$$\mathrm{Thank}\:\mathrm{you} \\ $$

Commented by Tinkutara last updated on 25/Mar/19

Ethanol forms hydrogen bonds with water

Commented by Hassen_Timol last updated on 25/Mar/19

Thank you

$${Thank}\:{you} \\ $$

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