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Question Number 57328 by ANTARES VY last updated on 02/Apr/19

Answered by mr W last updated on 02/Apr/19

$$let\alpha =\frac{\mathrm{\angle }A}{2}$$$$\sin \alpha =\frac{r}{AO}=\frac{2\times 3}{10}=\frac{3}{5}$$$$\Rightarrow \tan \alpha =\frac{3}{\sqrt{5^2-3^2}}=\frac{3}{4}$$$$BC=2\times (AO+r)\tan \alpha$$$$=2\times (\frac{10}{3}+2)\times \frac{3}{4}$$$$=8$$

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