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Question Number 57368 by problem solverd last updated on 03/Apr/19
53x−3−53x−5=615solveforx
Answered by tanmay.chaudhury50@gmail.com last updated on 03/Apr/19
53x=a53x53−53x−5=615a125−a=620a−125a125=620−124a=620×125a=−620×125124=−5×1251=−5453x=−54hereistheproblemarises..53xcannotbenegetive...
Commented by MJS last updated on 04/Apr/19
forx∈Cwe′dgetx=43+2n+13ln5πiwithn∈Z
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