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Question Number 57525 by Umar last updated on 06/Apr/19
Answered by tanmay.chaudhury50@gmail.com last updated on 07/Apr/19
$${c}=\frac{{q}}{{v}}=\frac{\mathrm{10}×\mathrm{10}^{−\mathrm{6}} }{\mathrm{10}}=\mathrm{10}^{−\mathrm{6}} {F} \\ $$$${v}=\frac{{q}}{{c}}=\frac{\mathrm{100}×\mathrm{10}^{−\mathrm{6}} }{\mathrm{10}^{−\mathrm{6}} }=\mathrm{100}\:{volt} \\ $$
Commented by Umar last updated on 07/Apr/19
$$\mathrm{thanks} \\ $$