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Question Number 57957 by rahul 19 last updated on 15/Apr/19

Commented by Smail last updated on 15/Apr/19

$$L_n=\frac{2^n+{(-2)}^n}{3^n}={\left(\frac{2}{3}\right)}^n(1+{(-1)}^n)$$$$Asn\to \mathrm{\infty },L_n\to 0because\frac{2}{3}<1$$$$However$$$$l_n=\frac{2^n+{(-2)}^n}{2^n}=1+{(-1)}^n$$$$\text{Double subscripts: use braces to clarify}$$$$\text{Double subscripts: use braces to clarify}$$$$\text{Double subscripts: use braces to clarify}$$

Commented by rahul 19 last updated on 16/Apr/19

$$ThankUSir.$$

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