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Question Number 57958 by rahul 19 last updated on 15/Apr/19

	Answered by tanmay.chaudhury50@gmail.com last updated on 15/Apr/19

	$(1, 4) a n d (3, 8)$ $c h o r d e q n y - 4 = (\frac{8 - 4}{3 - 1}) (x - 1)$ $y - 4 = 2 x - 2$ $y = 2 x + 2$ $e q n t a n g e n t ∥ t o c h o r d i s$ $y = 2 x + c$ $s o l v e y = 2 x + c s n d y = x^{2} - 2 x + 5$ $2 x + c = x^{2} - 2 x + 5$ $x^{2} - 4 x + 5 - c = 0$ $B^{2} - 4 A C = 0$ ${(- 4)}^{2} - 4 \times 1 \times (5 - c) = 0$ $16 - 20 + 4 c = 0$ $4 c = 4$ $c = 1$ $e q n t a n g e n t y = 2 x + 1$
	Commented by rahul 19 last updated on 15/Apr/19

	$t h a n k y o u s i r .$
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