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Question Number 57988 by peter frank last updated on 15/Apr/19

$$listallsubsetof$$$$\{2,4,6,7,8\}$$

Commented by mr W last updated on 16/Apr/19

$$thankssir!$$

Commented by mr W last updated on 17/Apr/19

$$\mathrm{\varnothing }\left(nullset\right)\Rightarrow 1=C_0^5$$$$\left\{2\right\}\left\{4\right\}\left\{6\right\}\left\{7\right\}\left\{8\right\}\Rightarrow 5=C_1^5$$$$\left\{24\right\}\left\{26\right\}\left\{27\right\}\left\{28\right\}\left\{46\right\}\left\{47\right\}\left\{48\right\}\left\{67\right\}\left\{67\right\}\left\{78\right\}\Rightarrow 10=C_2^5$$$$\left\{246\right\}\left\{247\right\}\left\{248\right\}\left\{267\right\}\left\{268\right\}\left\{278\right\}\left\{467\right\}\left\{468\right\}\left\{478\right\}\left\{678\right\}\Rightarrow 10=C_3^5$$$$\left\{2467\right\}\left\{2468\right\}\left\{2478\right\}\left\{2678\right\}\left\{4678\right\}\Rightarrow 5=C_4^5$$$$\left\{24678\right\}\Rightarrow 1=C_5^5$$$$\Rightarrow 32=2^5$$$$ingeneralasetwithnelementshas$$$$2^{n}subsets.$$

Commented by peter frank last updated on 15/Apr/19

$$thankyousir$$

Commented by Kunal12588 last updated on 16/Apr/19

$$ithink$$$$\varphi isalsoasubsetof\{2,4,6,7,8\}$$$$andeverysetisasubsetofitself$$$$\Rightarrow \{2,4,6,7,8\}\subseteq \{2,4,6,7,8\}$$$$soanswershouldbe{2}^5=32$$

Commented by problem solverd last updated on 16/Apr/19

$$\mathbf{but}\mathbf{the}\mathbf{question}\mathbf{was}\mathbf{to}\mathbf{list}$$$$\mathbf{all}\mathbf{subset}$$

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