Previous in Probability and Statistics Next in Probability and Statistics
Question Number 58051 by Aditya789 last updated on 17/Apr/19
Answered by tanmay last updated on 17/Apr/19
$${sample}\:{space}\left\{{HHH},{HHT},{HTH},{HTT},{THH}\right. \\ $$$$\left.\:\:\:\:\:{THT},{TTH},{TTT}\right\} \\ $$$${favourabe}\:{result}\:{is}\left\{{HT}\bar {{H}},{THT}\right\} \\ $$$${so}\:{probablity}=\frac{\mathrm{2}}{\mathrm{8}}=\frac{\mathrm{1}}{\mathrm{4}} \\ $$