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Question Number 58177 by mamah Fousséni last updated on 19/Apr/19

cos^(−1) (1/2) + 2 sin^(−1) (1/2)  =

$$\mathrm{cos}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{2}}\:+\:\mathrm{2}\:\mathrm{sin}^{−\mathrm{1}} \frac{\mathrm{1}}{\mathrm{2}}\:\:= \\ $$

Answered by math1967 last updated on 19/Apr/19

(π/3)+2×(π/6)=((2π)/3)

$$\frac{\pi}{\mathrm{3}}+\mathrm{2}×\frac{\pi}{\mathrm{6}}=\frac{\mathrm{2}\pi}{\mathrm{3}} \\ $$

Answered by tanmay last updated on 19/Apr/19

cos^(−1) (cos(π/3))+2sin^(−1) (sin(π/6))  =(π/3)+((2×π)/6)  =(π/3)+(π/3)=((2π)/3)

$${cos}^{−\mathrm{1}} \left({cos}\frac{\pi}{\mathrm{3}}\right)+\mathrm{2}{sin}^{−\mathrm{1}} \left({sin}\frac{\pi}{\mathrm{6}}\right) \\ $$$$=\frac{\pi}{\mathrm{3}}+\frac{\mathrm{2}×\pi}{\mathrm{6}} \\ $$$$=\frac{\pi}{\mathrm{3}}+\frac{\pi}{\mathrm{3}}=\frac{\mathrm{2}\pi}{\mathrm{3}} \\ $$$$ \\ $$

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