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Question Number 58203 by Umar last updated on 19/Apr/19

$$\mathrm{A}\mathrm{battery}\mathrm{can}\mathrm{supply}\mathrm{current}\mathrm{of}1.2\mathrm{A}$$$$\mathrm{and}0.4\mathrm{A}\mathrm{through}4\mathrm{\Omega }\mathrm{and}14\mathrm{\Omega }\mathrm{respectively}.$$$$\mathrm{Calculate}\mathrm{the}\mathrm{internal}\mathrm{resistance}\mathrm{of}\mathrm{the}\mathrm{battery}$$

Answered by mr W last updated on 19/Apr/19

$$letX=internalresistanceofbattery$$$$1.2\times (4+X)=0.4\times (14+X)$$$$\Rightarrow X=1\mathrm{\Omega }$$

Commented by Umar last updated on 19/Apr/19

$$\mathrm{thanks}$$

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