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Question Number 58377 by naka3546 last updated on 22/Apr/19

Answered by MJS last updated on 22/Apr/19

$$\mathrm{rectangular}\mathrm{triangle}\mathrm{with}\mathrm{diagonal}\mathrm{of}\mathrm{rectangle}$$$${(6-h)}^2+6^2={\left(2r\right)}^2$$$$\mathrm{short}\mathrm{side}\mathrm{of}\mathrm{rectangle}=2r-2h\Rightarrow$$$$2r=6+h$$$$$$$${(6-h)}^2+6^2={(6+h)}^2$$$$h=\frac{3}{2}$$$$r=\frac{15}{4}$$$$\mathrm{shaded}\mathrm{area}:6\times (6-h)=6\times \frac{9}{2}=27$$

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