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Question Number 58387 by azizullah last updated on 22/Apr/19

Answered by mr W last updated on 22/Apr/19

x=1 is a solution, ⇒a+5=3 ⇒a=−2 −2x^2 +5x−3=0 −(2x−3)(x−1)=0 ⇒x=1 ⇒x=(3/2)=other solution

x=1isasolution,⇒a+5=3⇒a=−2−2x2+5x−3=0−(2x−3)(x−1)=0⇒x=1⇒x=32=othersolution

Answered by Rasheed.Sindhi last updated on 22/Apr/19

α+β=−(5/a) , αβ=−(3/a) α=1⇒β=−(5/a)−1 & β=−(3/a) − ((5+a)/a)=−(3/a)⇒a=−2 β=−(3/a)=−(3/(−2))=(3/2)

α+β=−5a,αβ=−3aα=1⇒β=−5a−1&β=−3a−5+aa=−3a⇒a=−2β=−3a=−3−2=32

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