Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 58387 by azizullah last updated on 22/Apr/19

Answered by mr W last updated on 22/Apr/19

x=1 is a solution,  ⇒a+5=3  ⇒a=−2  −2x^2 +5x−3=0  −(2x−3)(x−1)=0  ⇒x=1  ⇒x=(3/2)=other solution

$${x}=\mathrm{1}\:{is}\:{a}\:{solution}, \\ $$$$\Rightarrow{a}+\mathrm{5}=\mathrm{3} \\ $$$$\Rightarrow{a}=−\mathrm{2} \\ $$$$−\mathrm{2}{x}^{\mathrm{2}} +\mathrm{5}{x}−\mathrm{3}=\mathrm{0} \\ $$$$−\left(\mathrm{2}{x}−\mathrm{3}\right)\left({x}−\mathrm{1}\right)=\mathrm{0} \\ $$$$\Rightarrow{x}=\mathrm{1} \\ $$$$\Rightarrow{x}=\frac{\mathrm{3}}{\mathrm{2}}={other}\:{solution} \\ $$

Answered by Rasheed.Sindhi last updated on 22/Apr/19

α+β=−(5/a) ,  αβ=−(3/a)  α=1⇒β=−(5/a)−1 & β=−(3/a)      − ((5+a)/a)=−(3/a)⇒a=−2      β=−(3/a)=−(3/(−2))=(3/2)

$$\alpha+\beta=−\frac{\mathrm{5}}{{a}}\:,\:\:\alpha\beta=−\frac{\mathrm{3}}{{a}} \\ $$$$\alpha=\mathrm{1}\Rightarrow\beta=−\frac{\mathrm{5}}{{a}}−\mathrm{1}\:\&\:\beta=−\frac{\mathrm{3}}{{a}} \\ $$$$\:\:\:\:−\:\frac{\mathrm{5}+{a}}{{a}}=−\frac{\mathrm{3}}{{a}}\Rightarrow{a}=−\mathrm{2} \\ $$$$\:\:\:\:\beta=−\frac{\mathrm{3}}{{a}}=−\frac{\mathrm{3}}{−\mathrm{2}}=\frac{\mathrm{3}}{\mathrm{2}} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com