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Question Number 58387 by azizullah last updated on 22/Apr/19
Answered by mr W last updated on 22/Apr/19
x=1isasolution,⇒a+5=3⇒a=−2−2x2+5x−3=0−(2x−3)(x−1)=0⇒x=1⇒x=32=othersolution
Answered by Rasheed.Sindhi last updated on 22/Apr/19
α+β=−5a,αβ=−3aα=1⇒β=−5a−1&β=−3a−5+aa=−3a⇒a=−2β=−3a=−3−2=32
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