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Question Number 58422 by peter frank last updated on 22/Apr/19

Answered by 2pac last updated on 23/Apr/19

$$DB=\frac{y}{sin\left(\beta \right)}$$$$<ADB=180-\alpha -\beta$$$$wehave\frac{DB}{sin\left(\alpha \right)}=\frac{AB}{sin(<ADB)}==>\frac{y}{sin\left(\alpha \right)}=\frac{AB}{sin(180-\alpha -\beta )}$$$$sin(180-z)=sinzso$$$$AB=\frac{y}{sin\left(\alpha \right)}\times sin(\alpha +\beta )$$$$$$

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