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Question Number 58558 by naka3546 last updated on 25/Apr/19

lim_(x→0)    ((√(2x^2  − 2ax + b − 3))/(x  ((x^5  + 8))^(1/3) ))  =  (2/3)  Value  of   ab  is  ...

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\:\frac{\sqrt{\mathrm{2}{x}^{\mathrm{2}} \:−\:\mathrm{2}{ax}\:+\:{b}\:−\:\mathrm{3}}}{{x}\:\:\sqrt[{\mathrm{3}}]{{x}^{\mathrm{5}} \:+\:\mathrm{8}}}\:\:=\:\:\frac{\mathrm{2}}{\mathrm{3}} \\ $$$${Value}\:\:{of}\:\:\:{ab}\:\:{is}\:\:... \\ $$

Answered by mr W last updated on 25/Apr/19

b=3  a=0  limit=((√2)/2)≠(2/3)  i think question is wrong.

$${b}=\mathrm{3} \\ $$$${a}=\mathrm{0} \\ $$$${limit}=\frac{\sqrt{\mathrm{2}}}{\mathrm{2}}\neq\frac{\mathrm{2}}{\mathrm{3}} \\ $$$${i}\:{think}\:{question}\:{is}\:{wrong}. \\ $$

Commented by naka3546 last updated on 25/Apr/19

may be,  it′s  wrong  problem .

$${may}\:{be},\:\:{it}'{s}\:\:{wrong}\:\:{problem}\:. \\ $$

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