Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 58567 by olalekan2 last updated on 25/Apr/19

 A regular polygon of (2k+1) sides  has 140 as the size of each interior  angle.Find k

$$\:{A}\:{regular}\:{polygon}\:{of}\:\left(\mathrm{2}{k}+\mathrm{1}\right)\:{sides} \\ $$$${has}\:\mathrm{140}\:{as}\:{the}\:{size}\:{of}\:{each}\:{interior} \\ $$$${angle}.{Find}\:{k} \\ $$

Commented by mr W last updated on 25/Apr/19

(2k+1)(180−140)=360  2k+1=9  k=4

$$\left(\mathrm{2}{k}+\mathrm{1}\right)\left(\mathrm{180}−\mathrm{140}\right)=\mathrm{360} \\ $$$$\mathrm{2}{k}+\mathrm{1}=\mathrm{9} \\ $$$${k}=\mathrm{4} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com