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Question Number 58853 by cesar.marval.larez@gmail.com last updated on 30/Apr/19

Answered by MJS last updated on 01/May/19

$$\frac{\frac{3}{2}{\sin }^3\frac{\pi }{2}+\cos \frac{2\pi }{3}}{\tan \frac{\pi }{3}+\cos -2\pi }=\frac{\frac{3}{2}\times 1^3-\frac{1}{2}}{\sqrt{3}+1}=\frac{1}{\sqrt{3}+1}=-\frac{1}{2}+\frac{\sqrt{3}}{2}$$

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