Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 58879 by gunawan last updated on 01/May/19

Answered by mr W last updated on 01/May/19

Commented by mr W last updated on 01/May/19

assume B(b,0) ⇒D(3, 3+b) D is on the circle, ⇒3^2 +(3+b)^2 =5^2 ⇒b^2 +6b−7=0 ⇒(b−1)(b−7)=0 ⇒b=1 C(b+3, b)=(4, 1) ⇒x=(√((5−4)^2 +1^2 ))=(√2)

assumeB(b,0)⇒D(3,3+b)Disonthecircle,⇒32+(3+b)2=52⇒b2+6b−7=0⇒(b−1)(b−7)=0⇒b=1C(b+3,b)=(4,1)⇒x=(5−4)2+12=2

Terms of Service

Privacy Policy

Contact: info@tinkutara.com