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Question Number 59012 by cesar.marval.larez@gmail.com last updated on 03/May/19

Answered by tanmay last updated on 03/May/19

182)∫((2x−7)/(x^2 +9))dx  ∫((d(x^2 +9))/(x^2 +9))−7∫(dx/(x^2 +3^2 ))  ln(x^2 +9)−7×(1/3)tan^(−1) ((x/3))+c

182)2x7x2+9dxd(x2+9)x2+97dxx2+32ln(x2+9)7×13tan1(x3)+c

Answered by tanmay last updated on 03/May/19

183)∫((x+3)/(√(1−x^2 )))dx  ∫(x/(√(1−x^2 )))dx+3∫(dx/(√(1−x^2 )))  x=sina    dx=cosada  ∫((sina)/(cosa))×cosada+3∫((cosada)/(cosa))  ∫sinada+3∫da  =−cosa+3a+c  =−(√(1−x^2 )) +3sin^(−1) (x)+c

183)x+31x2dxx1x2dx+3dx1x2x=sinadx=cosadasinacosa×cosada+3cosadacosasinada+3da=cosa+3a+c=1x2+3sin1(x)+c

Answered by tanmay last updated on 03/May/19

∫((4x+5)/(4x^2 +1))dx  (1/2)∫((d(4x^2 +1))/(4x^2 +1))+∫((5dx)/(4x^2 +1))  (1/2)∫((d(4x^2 +1))/(4x^2 +1))+(5/4)∫(dx/(x^2 +((1/2))^2 ))  (1/2)ln(4x^2 +1)+(5/4)×(1/(1/2))tan^(−1) ((x/(1/2)))+c  (1/2)ln(4x^2 +1)+(5/2)tan^(−1) (2x)+c

4x+54x2+1dx12d(4x2+1)4x2+1+5dx4x2+112d(4x2+1)4x2+1+54dxx2+(12)212ln(4x2+1)+54×112tan1(x12)+c12ln(4x2+1)+52tan1(2x)+c

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