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Question Number 59012 by cesar.marval.larez@gmail.com last updated on 03/May/19
Answered by tanmay last updated on 03/May/19
182)∫2x−7x2+9dx∫d(x2+9)x2+9−7∫dxx2+32ln(x2+9)−7×13tan−1(x3)+c
183)∫x+31−x2dx∫x1−x2dx+3∫dx1−x2x=sinadx=cosada∫sinacosa×cosada+3∫cosadacosa∫sinada+3∫da=−cosa+3a+c=−1−x2+3sin−1(x)+c
∫4x+54x2+1dx12∫d(4x2+1)4x2+1+∫5dx4x2+112∫d(4x2+1)4x2+1+54∫dxx2+(12)212ln(4x2+1)+54×112tan−1(x12)+c12ln(4x2+1)+52tan−1(2x)+c
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