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Question Number 59201 by otchereabdullai@gmail.com last updated on 05/May/19

$$\mathrm{make}\mathrm{x}\mathrm{the}\mathrm{subject}\mathrm{of}\mathrm{x}=\mathrm{m}+\mathrm{x}$$

Commented by Forkum Michael Choungong last updated on 05/May/19

$$x-x=m$$$$x(1-1)=m$$$$\Rightarrow x=\frac{m}{(1-1)}$$$$$$$$generallythatsnottruesince$$$$1-1=0$$$$x=\mathrm{\infty }$$

Commented by otchereabdullai@gmail.com last updated on 05/May/19

$$\mathrm{thanks}\mathrm{sir}$$

Commented by Senior Sun last updated on 06/May/19

$$whatdoyoumeaninyoursolution?$$

Commented by Forkum Michael Choungong last updated on 06/May/19

$$imean\frac{m}{0}isundefined$$

Answered by MJS last updated on 05/May/19

$${\mathrm{it}}^{\prime }\mathrm{s}\mathrm{impossible}$$$$x=m+x\Rightarrow \mathrm{\forall }x:m=0$$

Commented by otchereabdullai@gmail.com last updated on 05/May/19

$$\mathrm{thanks}\mathrm{prof}$$

Commented by otchereabdullai@gmail.com last updated on 05/May/19

$$\mathrm{I}\mathrm{thought}\mathrm{there}\mathrm{is}\mathrm{a}\mathrm{different}\mathrm{approach}$$$$\mathrm{to}\mathrm{such}\mathrm{qustion}$$

Answered by malwaan last updated on 06/May/19

$$x-x=m$$$$x(1-1)=m$$$$x\times 0=m$$$$thereisnosolution$$$$solutionset=\mathrm{\varnothing }$$

Commented by otchereabdullai@gmail.com last updated on 06/May/19

$$\mathrm{thanks}$$

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