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Question Number 59323 by Tawa1 last updated on 08/May/19

Answered by tanmay last updated on 08/May/19

$$whencabcatchbusthatbothcoversamedistance$$$$d_{cab}=\frac{1}{2}\times 2\times t^2$$$$d_{bus}=30(t+5)$$$$t^2=30t+150$$$$t^2-30t-150=0$$$$t^2-2\times t\times 15+225=150+225$$$${(t-15)}^2=375$$$$t=15+5\sqrt{15}$$$$t\approx 34.36sec$$$$d_{cab}=t^2$$$$d_{cab}\approx 1180.61meter$$

Commented by Tawa1 last updated on 08/May/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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