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Question Number 59547 by hhghg last updated on 11/May/19

$$4+\mathrm{t}\times \mathrm{c}\mathrm{t}=3\mathrm{c}=6$$

Answered by Forkum Michael Choungong last updated on 11/May/19

$$4+t\times 6t=3$$$$6t^2+1=0$$$$6t^2=-1$$$$t^2=-\frac{1}{6}$$$$t=\frac{i}{6}or-\frac{i}{6}$$

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