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Question Number 59595 by Gulay last updated on 12/May/19

Commented by Gulay last updated on 12/May/19

$$\mathrm{sir}\mathrm{could}\mathrm{you}\mathrm{belp}\mathrm{me}$$

Answered by tanmay last updated on 12/May/19

$$\underset{x\to 4}{\lim }\left(\frac{x+4-8}{x^2-16}\right)$$$$\underset{x\to 4}{\lim }\left\{\frac{x-4}{(x+4)(x-4)}\right\}$$$$=\frac{1}{4+4}$$$$=\frac{1}{8}$$

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