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Question Number 59667 by tanmay last updated on 13/May/19

Answered by tanmay last updated on 13/May/19

$${\int }_a^{b}f\left(x\right)dx={\int }_a^{b}f(a+b-x)dx$$$$I={\int }_4^{10}\frac{\left[x^2\right]}{\left[{(x-14)}^2\right]+\left[x^2\right]}dx$$$$I={\int }_4^{10}\frac{\left[{(14-x)}^2\right]}{\left[x^2\right]+\left[{(14-x)}^2\right]}dx$$$$2I={\int }_4^{10}dx$$$$I=3$$

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