Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 59787 by Khairun Nisa last updated on 14/May/19

Answered by MJS last updated on 14/May/19

$$\mathrm{both}\mathrm{should}\mathrm{be}\mathrm{square}\mathrm{numbers},\mathrm{trying}\mathrm{I}\mathrm{get}$$$$x=9$$$$y=4$$$$$$$$\sqrt{x}+y=7\Rightarrow y=7-\sqrt{x}$$$$\mathrm{this}\mathrm{is}\mathrm{a}\mathrm{half}\mathrm{parabola}$$$$x+\sqrt{y}=11\Rightarrow x=11-\sqrt{y}$$$$\mathrm{this}\mathrm{is}\mathrm{a}\mathrm{half}\mathrm{parabola}\mathrm{too}$$$$\Rightarrow {\mathrm{there}}^{\prime }\mathrm{s}\mathrm{only}\mathrm{one}\mathrm{intersection}$$

Answered by behi83417@gmail.com last updated on 15/May/19

$$(\sqrt{x}-3)+(y-4)=0$$$$(x-9)+(\sqrt{y}-2)=0$$$$\Rightarrow \{\begin{array}{l}(\sqrt{x}-3)+(\sqrt{y}-2)(\sqrt{y}+2)=0\\ (\sqrt{x}-3)(\sqrt{x}+3)+(\sqrt{y}-2)=0\end{array}$$$$\Rightarrow \{\begin{array}{l}(\sqrt{x}-3)-(\sqrt{x}-3)(\sqrt{x}+3)(\sqrt{y}+2)=0\\ \Rightarrow (\sqrt{x}-3)[1-(\sqrt{x}+3)(\sqrt{y}+2)]=0\end{array}$$$$\Rightarrow \sqrt{x}-3=0\Rightarrow \sqrt{x}=3\Rightarrow [\mathbf{x}=9]$$$$x=9\Rightarrow \sqrt{y}=11-9=2\Rightarrow [\mathbf{y}=4].◼$$

Commented by Kunal12588 last updated on 15/May/19

$$great!$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com