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Question Number 59905 by Sardor2211 last updated on 15/May/19

∫(2x−1)^� 20

Missing \left or extra \right

Commented by maxmathsup by imad last updated on 16/May/19

if you mean I =∫ (2x−1)^(20) dx ⇒I =∫ Σ_(k=0) ^(20) C_(20) ^k (2x)^k (−1)^(20−k) dx =Σ_(k=0) ^(20) 2^k (−1)^(20−k) C_(20) ^k ∫ x^k dx =Σ_(k=0) ^(20) 2^k (−1)^k C_(20) ^k (1/(k+1)) +C

ifyoumeanI=∫(2x−1)20dx⇒I=∫∑k=020C20k(2x)k(−1)20−kdx=∑k=0202k(−1)20−kC20k∫xkdx=∑k=0202k(−1)kC20k1k+1+C

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