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Question Number 59960 by cesar.marval.larez@gmail.com last updated on 16/May/19

Answered by MJS last updated on 16/May/19

$$\mathrm{I}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{understand}\mathrm{the}\mathrm{question}$$$$\mathrm{is}A\mathrm{the}\mathrm{source}\mathrm{or}\mathrm{the}\mathrm{target}\mathrm{of}\mathrm{the}\mathrm{vectors}?$$$$\mathrm{if}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{the}\mathrm{source}$$$$X=A+\overrightarrow{\mathfrak{v}}=(a,b)+(v,w)=(a+v,b+w)$$$$\mathrm{if}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{the}\mathrm{target}$$$$X+\overrightarrow{\mathfrak{v}}=A\Rightarrow X=A-\overrightarrow{\mathfrak{v}}=(a,b)-(v,w)=(a-v,b-w)$$

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