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Question Number 59974 by vajpaithegrate@gmail.com last updated on 16/May/19

Answered by tanmay last updated on 16/May/19

$$lateralsurfacearea=\pi rl$$$$givencos{45}^o=\frac{h}{l}$$$$l=\frac{h}{cos{45}^o}=h\sqrt{2}$$$$tan{45}^o=\frac{r}{h}$$$$r=htan{45}^o=h$$$$lateralzurfacearea=\pi rl$$$$=\frac{22}{7}\times h\times h\sqrt{2}$$$$$$$$=\pi \times {(20.025)}^2\times \sqrt{2}$$$$\approx 401\sqrt{2}\pi$$$$plscheck...$$

Commented by vajpaithegrate@gmail.com last updated on 16/May/19

$$\mathrm{thank}\mathrm{u}\mathrm{sir}$$

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