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Question Number 59975 by vajpaithegrate@gmail.com last updated on 16/May/19

Answered by tanmay last updated on 16/May/19

$$T.S.Aofcone=\pi rl+\pi r^2$$$$T.S.A=\pi r(r+\sqrt{h^2+r^2})]]when[l^2=r^2+h^2]$$$$\frac{dS}{dh}=\pi r(0+\frac{1}{2\sqrt{h^2+r^2}}\times 2h)$$$$dS=\left(\frac{h}{\sqrt{h^2+r^2}}\times dh\right)\times \pi r$$$$dS=\frac{\pi rh}{\sqrt{h^2+r^2}}\times \alpha [givendh=\alpha ]$$$$$$

Commented by vajpaithegrate@gmail.com last updated on 16/May/19

$$\mathrm{thank}\mathrm{u}\mathrm{sir}$$

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