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Question Number 60423 by Tawa1 last updated on 20/May/19

Answered by MJS last updated on 20/May/19

(((20)),((∠30°)) ) = (((10(√3))),((10)) ) ((8),((∠−50°)) ) = (((8sin ((2π)/9))),((−8cos ((2π)/9))) ) (((10(√3))),((10)) ) + (((8sin ((2π)/9))),((−8cos ((2π)/9))) ) ≈ (((22.46)),((3.87)) ) the length of this vector is 22.79 the direction of this vector is E 9.78° N

$$\begin{pmatrix}{\mathrm{20}}\\{\angle\mathrm{30}°}\end{pmatrix}\:=\begin{pmatrix}{\mathrm{10}\sqrt{\mathrm{3}}}\\{\mathrm{10}}\end{pmatrix} \\ $$$$\begin{pmatrix}{\mathrm{8}}\\{\angle−\mathrm{50}°}\end{pmatrix}\:=\begin{pmatrix}{\mathrm{8sin}\:\frac{\mathrm{2}\pi}{\mathrm{9}}}\\{−\mathrm{8cos}\:\frac{\mathrm{2}\pi}{\mathrm{9}}}\end{pmatrix} \\ $$$$\begin{pmatrix}{\mathrm{10}\sqrt{\mathrm{3}}}\\{\mathrm{10}}\end{pmatrix}\:+\begin{pmatrix}{\mathrm{8sin}\:\frac{\mathrm{2}\pi}{\mathrm{9}}}\\{−\mathrm{8cos}\:\frac{\mathrm{2}\pi}{\mathrm{9}}}\end{pmatrix}\:\approx\begin{pmatrix}{\mathrm{22}.\mathrm{46}}\\{\mathrm{3}.\mathrm{87}}\end{pmatrix} \\ $$$$\mathrm{the}\:\mathrm{length}\:\mathrm{of}\:\mathrm{this}\:\mathrm{vector}\:\mathrm{is}\:\mathrm{22}.\mathrm{79} \\ $$$$\mathrm{the}\:\mathrm{direction}\:\mathrm{of}\:\mathrm{this}\:\mathrm{vector}\:\mathrm{is}\:\mathrm{E}\:\mathrm{9}.\mathrm{78}°\:\mathrm{N} \\ $$

Commented by Tawa1 last updated on 20/May/19

God bless you sir

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

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