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Question Number 6045 by sanusihammed last updated on 10/Jun/16
4x=2xfindx
Commented by Yozzii last updated on 10/Jun/16
4x=2x22x=2x−1=−2x(2−2x)−1=−2xeln2−2x−1=−2xe−2xln2−ln2=(−2xln2)e−2xln2⇒W(−ln2)=−2xln2x=−W(−ln2)2ln2(FollowingPrakash′sexample)
Answered by Yozzii last updated on 11/Jun/16
x=−W(−ln2)2ln2
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