Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 6045 by sanusihammed last updated on 10/Jun/16

4^x  = 2x    find x

4x=2xfindx

Commented by Yozzii last updated on 10/Jun/16

4^x =2x  2^(2x) =2x  −1=−2x(2^(−2x) )  −1=−2xe^(ln2^(−2x) )   −1=−2xe^(−2xln2)   −ln2=(−2xln2)e^(−2xln2)   ⇒W(−ln2)=−2xln2  x=−((W(−ln2))/(2ln2))    (Following Prakash′s example)

4x=2x22x=2x1=2x(22x)1=2xeln22x1=2xe2xln2ln2=(2xln2)e2xln2W(ln2)=2xln2x=W(ln2)2ln2(FollowingPrakashsexample)

Answered by Yozzii last updated on 11/Jun/16

x=−((W(−ln2))/(2ln2))

x=W(ln2)2ln2

Terms of Service

Privacy Policy

Contact: info@tinkutara.com