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Question Number 60475 by Tawa1 last updated on 21/May/19

Answered by tanmay last updated on 21/May/19

$$\frac{dp}{dx}=\frac{f\left(x\right)\frac{dg\left(x\right)}{dx}-[g\left(x\right)-1]\frac{df\left(x\right)}{dx}}{{\left\{f\left(x\right)\right\}}^2}$$$$p^{\prime }\left(2\right)=\frac{f\left(2\right)g^{\prime }\left(2\right)-[g\left(2\right)-1]f^{\prime }\left(2\right)}{f^2\left(2\right)}$$$$=\frac{(-1)(-sin2)-[cos2-1]5}{{(-1)}^2}$$$$=sin2-5cos2+5$$$$=7.99$$

Commented by Tawa1 last updated on 21/May/19

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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