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Question Number 60576 by hovea cw last updated on 22/May/19

$$\mathrm{two}\mathrm{faire}\mathrm{dices}\mathrm{are}\mathrm{tossed}\mathrm{together}$$$$\mathrm{find}\mathrm{the}\mathrm{probability}\mathrm{that}\mathrm{the}$$$$\mathrm{total}\mathrm{score}\mathrm{is}\mathrm{atmost}4$$$$$$

Commented by hovea cw last updated on 22/May/19

$$\mathrm{help}\mathrm{plzx}$$

Commented by mr W last updated on 22/May/19

$$1+1$$$$1+2$$$$2+2$$$$1+3$$$$sum=2\times 4=8$$$$total6\times 6=36$$$$\Rightarrow p=\frac{8}{36}=\frac{2}{9}$$

Commented by hovea cw last updated on 22/May/19

$$\mathrm{ttanks}\mathrm{sir}$$

Commented by MJS last updated on 22/May/19

$$\mathrm{sorry}\mathrm{but}\mathrm{this}\mathrm{is}\mathrm{not}\mathrm{true}$$

Answered by MJS last updated on 22/May/19

$$11$$$$12,21$$$$13,31$$$$22$$$$=6\mathrm{possible}\mathrm{combinations}$$$$141516$$$$23242526$$$$3233343536$$$$414243444546$$$$515253545556$$$$616263646566$$$$=30$$$$\Rightarrow \frac{6}{36}=\frac{1}{6}$$

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