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Question Number 60588 by behi83417@gmail.com last updated on 22/May/19

Commented by behi83417@gmail.com last updated on 22/May/19

$$AD\mathrm{\&}CEareangularbisectorof$$$$\measuredangle A\mathrm{\&}\measuredangle C.$$$$DG\mathrm{\perp }AB,EF\mathrm{\perp }BC,BH\mathrm{\perp }DE,DE=\frac{1}{2}AC.$$$$\Rightarrow \frac{BH}{DG+EF}=?$$

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