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Question Number 60631 by aliesam last updated on 23/May/19

$$\mathrm{prove}\mathrm{that}\underset{-\mathrm{\infty }}{\stackrel{\mathrm{\infty }}{\int }}{\mathrm{x}}^5{\mathrm{e}}^{-{\mathrm{x}}^2}\sin \left({\mathrm{x}}^3\right)\mathrm{dx}=0.25474$$

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