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Question Number 60791 by arcana last updated on 25/May/19

∫(e^n /x^(n+1) )dx, n∈N

enxn+1dx,nN

Commented by Forkum Michael Choungong last updated on 25/May/19

∫(e^n /x^(n+1) )dx = e^n ∫(1/x^(n+1 ) )dx                     = −e^n ((1/(nx^n ))) where n∈N

enxn+1dx=en1xn+1dx=en(1nxn)wherenN

Commented by arcana last updated on 25/May/19

thanks

thanks

Answered by MJS last updated on 25/May/19

∫(e^n /x^(n+1) )dx=e^n ∫(dx/x^(n+1) )=−(e^n /(nx^n ))+C with n≠0

enxn+1dx=endxxn+1=ennxn+Cwithn0

Commented by arcana last updated on 25/May/19

thanks

thanks

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