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Question Number 61027 by Gulay last updated on 28/May/19

Commented by Gulay last updated on 28/May/19

sir could you help me

$$\mathrm{sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me} \\ $$

Commented by mathsolverby Abdo last updated on 28/May/19

={(1+i)(1−i)}^7 =(1−i^2 )^7 =2^7

$$=\left\{\left(\mathrm{1}+{i}\right)\left(\mathrm{1}−{i}\right)\right\}^{\mathrm{7}} =\left(\mathrm{1}−{i}^{\mathrm{2}} \right)^{\mathrm{7}} =\mathrm{2}^{\mathrm{7}} \\ $$

Commented by Gulay last updated on 28/May/19

thank you sir

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$

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