Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 61048 by Gulay last updated on 28/May/19

Commented by Gulay last updated on 28/May/19

AB=30    BD=24   Find DC   <B=90  sir plz help me

$$\mathrm{AB}=\mathrm{30}\:\:\:\:\mathrm{BD}=\mathrm{24}\:\:\:\mathrm{Find}\:\mathrm{DC}\:\:\:<\mathrm{B}=\mathrm{90} \\ $$$$\mathrm{sir}\:\mathrm{plz}\:\mathrm{help}\:\mathrm{me} \\ $$

Answered by mr W last updated on 28/May/19

AD=(√(AB^2 −BD^2 ))=(√(30^2 −24^2 ))=18  ((DC)/(BD))=((BD)/(AD))  ⇒DC=((BD^2 )/(AD))=((24^2 )/(18))=32

$${AD}=\sqrt{{AB}^{\mathrm{2}} −{BD}^{\mathrm{2}} }=\sqrt{\mathrm{30}^{\mathrm{2}} −\mathrm{24}^{\mathrm{2}} }=\mathrm{18} \\ $$$$\frac{{DC}}{{BD}}=\frac{{BD}}{{AD}} \\ $$$$\Rightarrow{DC}=\frac{{BD}^{\mathrm{2}} }{{AD}}=\frac{\mathrm{24}^{\mathrm{2}} }{\mathrm{18}}=\mathrm{32} \\ $$

Commented by kaivan.ahmadi last updated on 28/May/19

if AD^� B=90 this is true

$${if}\:{A}\hat {{D}B}=\mathrm{90}\:{this}\:{is}\:{true}\: \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com