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Question Number 61318 by Tawa1 last updated on 31/May/19

	Answered by tanmay last updated on 01/Jun/19

	${\vec{V}}_{t r a i n w . r . t g r o u n d} = (\frac{64000}{3600}) m / s \vec{i} = (\frac{160}{9}) m / s \vec{i}$ ${\vec{V}}_{r a i n w . r . t g r o u n d} = 5 m / s (- \vec{k})$ $i t h i n k a p p e r e n t v e l o c i t y o f r a i n t 0 b e f o u n d$ ${(\vec{V})}_{w . r . t t r a i n}^{r a i n} = {(\vec{V})}_{g r o u n d}^{r a i n} - {(\vec{V})}_{g r o u n d}^{t r a i n} = - 5 \vec{k} - \frac{160}{9} \vec{i}$ $r e s u l t a n t = \sqrt{{(- 5)}^{2} + {(\frac{- 160}{9})}^{2}} \approx 18.47 m / s (a p p r o x)$ $d i r e c t i o n t a n α = \frac{- 5}{\frac{- 160}{9}} = \frac{45}{160} = 0.28125 = t a n 15 . 7^{o} (a p p r o x) w i t h t h e d i r e c t i o n$ $o f t r a i n . . .$ $p l s c h e c k . . .$
	Commented by Tawa1 last updated on 01/Jun/19

	$God bless you sir$
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