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Question Number 6145 by Ninik last updated on 16/Jun/16

$$showthat\sin {64}^{°}\times \cos {26}^{°}+\cos {64}^{°}\times \sin {26}^{°}=1$$$$$$

Answered by Rasheed Soomro last updated on 16/Jun/16

$$\sin {64}^{°}\times \cos {26}^{°}+\cos {64}^{°}\times \sin {26}^{°}=1$$$$LHS=\sin (64+26)=\sin 90=1=RHS$$$$Formulaused:$$$$\sin \alpha \cos \beta +\cos \alpha \sin \beta =\sin (\alpha +\beta )$$

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