(√(a−(√(a+x))))+(√(a+(√(a−x))))=2x this is the solution Sir Aifour and me found trivial solution a=x=0 a, x ∈R x=((√2)/8)(r+(√(r^2 +4)))(√(2(4a−1)−r^2 −r(√(r^2 +4)))) with r=−2(√((4a−3)/3))sin ((1/3)arcsin ((3(√3))/((4a−3)^(3/2) ))) no solution for a<a_0 with a


Question and Answers Forum

All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 61490 by MJS last updated on 03/Jun/19

$\sqrt{a - \sqrt{a + x}} + \sqrt{a + \sqrt{a - x}} = 2 x$ $this is the solution Sir Aifour and me found$ $trivial solution a = x = 0$ $a, x \in R$ $x = \frac{\sqrt{2}}{8} (r + \sqrt{r^{2} + 4}) \sqrt{2 (4 a - 1) - r^{2} - r \sqrt{r^{2} + 4}}$ $with$ $r = - 2 \sqrt{\frac{4 a - 3}{3}} \sin (\frac{1}{3} \arcsin \frac{3 \sqrt{3}}{{(4 a - 3)}^{\frac{3}{2}}})$ $no solution for a < a_{0} with a_{0} \approx 1.509830340886$
Commented by MJS last updated on 03/Jun/19

Commented by maxmathsup by imad last updated on 03/Jun/19

$t h a n k s s i r m j s a n d s i r a j f o u r . . .$
Commented by MJS last updated on 03/Jun/19
The path had been found by Sir Aifour, I added some odds and ends. So it's an Indian-Austrian team work ��
Commented by behi83417@gmail.com last updated on 03/Jun/19

$great job done by : MJS & Ajfour .$ $congratulation to you two and forum!$
Commented by Rasheed.Sindhi last updated on 08/Jun/19
${(A/M)J^( ⧫) (S/4)}$
${\frac{A}{M} \overset{⧫}{J} \frac{S}{4}}$
Commented by ajfour last updated on 03/Jun/19

$T h a n k s E v e r y o n e & d e a r M j S S i r .$
Commented by Tawa1 last updated on 03/Jun/19

$Wow, that is great sirs$
Commented by mr W last updated on 03/Jun/19

$w o w! f a n t a s t i c!$
Commented by ajfour last updated on 04/Jun/19

Commented by ajfour last updated on 04/Jun/19

$A r e p r e s e n t a t i o n (g e o m e t r i c) .$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum