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Question Number 61569 by Tawa1 last updated on 04/Jun/19

Commented by tanmay last updated on 04/Jun/19

Commented by tanmay last updated on 04/Jun/19

∠CDP=x  ∠EDP=26  DP∥  BC and DP∥ EF

$$\angle{CDP}={x}\:\:\angle{EDP}=\mathrm{26} \\ $$$${DP}\parallel\:\:{BC}\:{and}\:{DP}\parallel\:{EF} \\ $$

Commented by Tawa1 last updated on 04/Jun/19

God bless you sir

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

Answered by tanmay last updated on 04/Jun/19

x+y=360^o   x+26^o =75^o    x=49   y=311^o

$${x}+{y}=\mathrm{360}^{{o}} \\ $$$${x}+\mathrm{26}^{{o}} =\mathrm{75}^{{o}} \:\:\:{x}=\mathrm{49}\:\:\:{y}=\mathrm{311}^{{o}} \\ $$

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