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Question Number 61719 by aliesam last updated on 06/Jun/19
∫dx2+sin(x)
Commented by maxmathsup by imad last updated on 07/Jun/19
letA=∫dx2+sinx⇒A=tan(x2)=t∫12+2t1+t22dt1+t2=2∫dt2+2t2+2t=∫dtt2+t+1=∫dt(t+12)2+34=t+12=32u=43∫11+u232du=23arctan(u)+c=23arctan(2t+13)+c=23arctan(23tan(x2)+13)+c.
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