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Question Number 61738 by rajesh4661kumar@gamil.com last updated on 07/Jun/19

Answered by MJS last updated on 07/Jun/19

$$\mathrm{strictly}\mathrm{logical}$$$$ABA\Rightarrow B$$$$falsefalsetrue$$$$falsetruetrue$$$$truefalsefalse$$$$truetruetrue$$$$[(1+2=6)\wedge (2+3=8)\wedge (3+4=9)]\Rightarrow 8+9=\frac{7}{13}\pi \left(\mathrm{or}\mathrm{whatever}\mathrm{you}\mathrm{want}\right)$$$$$$$$\mathrm{but}\mathrm{of}\mathrm{course}\mathrm{the}\mathrm{question}{\mathrm{isn}}^{\prime }\mathrm{t}\mathrm{meant}\mathrm{this}\mathrm{way}$$

Answered by Rasheed.Sindhi last updated on 08/Jun/19

$$\underset{⌣}{\stackrel{⌢}{⟨1+2=6⟩}}$$$$\lceil \frac{12}{2}\rceil =\lceil 6\rceil =6$$$$\underset{⌣}{\stackrel{⌢}{⟨2+3=8⟩}}$$$$\lceil \frac{23}{3}\rceil =\lceil 7.\bar{6}\rceil =8$$$$\underset{⌣}{\stackrel{⌢}{⟨3+4=9⟩}}$$$$\lceil \frac{34}{4}\rceil =\lceil 8.5\rceil =9$$$$\underset{⌣}{\stackrel{⌢}{⟨8+9=?⟩}}$$$$\lceil \frac{89}{9}\rceil =\lceil 9.\bar{8}\rceil =10$$$$$$$$$$$$\mathbf{t}\oplus (\mathbf{t}+1)=\lceil \frac{10\mathrm{t}+(\mathrm{t}+1)}{\mathrm{t}+1}\rceil$$$$[\rceil \mathrm{is}\mathrm{ceiling}\mathrm{function}.$$

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