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Question Number 61873 by lalitchand last updated on 10/Jun/19

((30x^8 y^(12) ))^(1/3) /^4 (√(6x^2 y^9 z))    simplifh this question

30x8y123/46x2y9zsimplifhthisquestion

Commented by MJS last updated on 10/Jun/19

please make clear if it′s really y12

pleasemakeclearifitsreallyy12

Commented by lalitchand last updated on 10/Jun/19

yes its power

yesitspower

Answered by MJS last updated on 10/Jun/19

((30^(1/3) x^(8/3) y^(12/3) )/(6^(1/4) x^(2/4) y^(9/4) z^(1/4) ))=((2^(1/3) 3^(1/3) 5^(1/3) x^(8/3) y^4 )/(2^(1/4) 3^(1/4) x^(1/2) y^(9/4) z^(1/4) ))=  =2^((1/3)−(1/4)) 3^((1/3)−(1/4)) 5^(1/3) x^((8/3)−(1/2)) y^(4−(9/4)) z^(−(1/4)) =  =2^(1/(12)) 3^(1/(12)) 5^(1/3) x^((13)/6) y^(7/4) z^(−(1/4)) =((6^(1/12) 5^(1/3) x^(13/6) y^(7/4) )/z^(1/4) )=  not sure what would be more simple  =(((3750x^(26) y^(21) )/z^3 ))^(1/(12))

301/3x8/3y12/361/4x2/4y9/4z1/4=21/331/351/3x8/3y421/431/4x1/2y9/4z1/4==2131431314513x8312y494z14==21123112513x136y74z14=61/1251/3x13/6y7/4z1/4=notsurewhatwouldbemoresimple=3750x26y21z312

Commented by lalitchand last updated on 10/Jun/19

this is what i got but kn answer sheet it was different

thisiswhatigotbutknanswersheetitwasdifferent

Commented by MJS last updated on 10/Jun/19

then the answer sheet is wrong

thentheanswersheetiswrong

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