Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 61873 by lalitchand last updated on 10/Jun/19

$$\sqrt[3]{{30\mathrm{x}}^8{\mathrm{y}}^{12}}{/}^4\sqrt{{6\mathrm{x}}^2{\mathrm{y}}^9\mathrm{z}}\mathrm{simplifh}\mathrm{this}\mathrm{question}$$

Commented by MJS last updated on 10/Jun/19

$$\mathrm{please}\mathrm{make}\mathrm{clear}\mathrm{if}{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{really}y12$$

Commented by lalitchand last updated on 10/Jun/19

$$\mathrm{yes}\mathrm{its}\mathrm{power}$$

Answered by MJS last updated on 10/Jun/19

$$\frac{{30}^{1/3}{x}^{8/3}{y}^{12/3}}{6^{1/4}{x}^{2/4}{y}^{9/4}{z}^{1/4}}=\frac{2^{1/3}{3}^{1/3}{5}^{1/3}{x}^{8/3}{y}^4}{2^{1/4}{3}^{1/4}{x}^{1/2}{y}^{9/4}{z}^{1/4}}=$$$$=2^{\frac{1}{3}-\frac{1}{4}}{3}^{\frac{1}{3}-\frac{1}{4}}{5}^{\frac{1}{3}}{x}^{\frac{8}{3}-\frac{1}{2}}{y}^{4-\frac{9}{4}}{z}^{-\frac{1}{4}}=$$$$=2^{\frac{1}{12}}{3}^{\frac{1}{12}}{5}^{\frac{1}{3}}{x}^{\frac{13}{6}}{y}^{\frac{7}{4}}{z}^{-\frac{1}{4}}=\frac{6^{1/12}{5}^{1/3}{x}^{13/6}{y}^{7/4}}{z^{1/4}}=$$$$\mathrm{not}\mathrm{sure}\mathrm{what}\mathrm{would}\mathrm{be}\mathrm{more}\mathrm{simple}$$$$=\sqrt[12]{\frac{3750x^{26}{y}^{21}}{z^3}}$$

Commented by lalitchand last updated on 10/Jun/19

$$\mathrm{this}\mathrm{is}\mathrm{what}\mathrm{i}\mathrm{got}\mathrm{but}\mathrm{kn}\mathrm{answer}\mathrm{sheet}\mathrm{it}\mathrm{was}\mathrm{different}$$

Commented by MJS last updated on 10/Jun/19

$$\mathrm{then}\mathrm{the}\mathrm{answer}\mathrm{sheet}\mathrm{is}\mathrm{wrong}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com