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Question Number 61874 by aliesam last updated on 10/Jun/19
∫xln(x)−xln3(x)dx
Commented by Prithwish sen last updated on 10/Jun/19
∫[x[ln(x)]2−x[ln(x)]3]dxapplyingbyparts=x22[ln(x)]2+∫x[ln(x)]3dx−∫x[ln(x)]3+C=x22[ln(x)]2+C
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