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Question Number 62036 by Cypher1207 last updated on 14/Jun/19

$$\mathrm{Correct}\mathrm{me}\mathrm{if}\mathrm{I}\mathrm{am}\mathrm{wrong}.$$$$\underset{\sqrt{-1}=1}{\sum ^3}{\mathrm{x}}_{\sqrt{-1}}+{\mathrm{y}}_{\sqrt{-1}}$$$$\therefore (i=\sqrt{-1})$$$$$$

Commented by Rasheed.Sindhi last updated on 15/Jun/19

$$\sqrt{-1}=1???\sqrt{-1}\ne 1$$$$i\mathrm{is}\mathrm{not}\mathrm{variable}.\mathrm{It}\mathrm{cannot}\mathrm{hold}\mathrm{values}$$$$1\mathrm{through}3.$$

Commented by Cypher1207 last updated on 16/Jun/19

$$\mathrm{hey}\mathrm{calm}\mathrm{down}...\mathrm{read}\mathrm{the}\mathrm{last}$$$$\mathrm{phrase}.$$

Commented by Rasheed.Sindhi last updated on 16/Jun/19

$$\mathrm{hahaha}...$$

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