Question Number 62054 by hhghg last updated on 14/Jun/19 | ||
$$\mathrm{484}×\mathrm{27} \\ $$ | ||
Commented by Tony Lin last updated on 15/Jun/19 | ||
$$=\mathrm{11}^{\mathrm{2}} ×\mathrm{6}^{\mathrm{2}} ×\mathrm{3} \\ $$$$=\left(\mathrm{108}×\mathrm{11}\right)×\mathrm{11} \\ $$$$=\mathrm{1188}×\mathrm{11} \\ $$$$=\mathrm{13068} \\ $$ | ||