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Question Number 6251 by net last updated on 20/Jun/16
3x−2y−4z=23y−4z=−22y+6z=−1
Answered by Rasheed Soomro last updated on 20/Jun/16
3x−2y−4z=2.........(i)3y−4z=−2.............(ii)2y+6z=−1.............(iii)2×(ii):6y−8z=−4.......(iv)3×(iii):6y+18z=−3.......(v)(iv)−(v):−26z=−1⇒z=126Substitutingz=126in(ii)3y−4(126)=−2⇒3y=−2+213=−2413⇒y=−2439Substitutingvaluesofyandzin(i)3x−2(−2439)−4(126)=23x+4839−213=2⇒117x+48−6=78x=78−42117=36117=413⇒x=413
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